© Mislav Predavec, April 2026.
Last Revised: 30/Apr/26.
A number is said to be transcendent if it is not algebraic (lat. transcendens - above limits, beyond experience or supremely excellent). In that sense, this test is a complement to high range IQ test Algebrica. The fee is 40€(50$) in cash or 50€(60$) by bank transfer (hover over email), NO PAYPAL. Answers may be sent by e-mail or by mail with the fee enclosed on the address: Mislav Predavec, Jakova Gotovca 2, 10000 Zagreb, Croatia. The certificate of this test is available in electronic form (30€). A current score list and norm can be found on the link provided. The raw score follows asap. This test is currently accepted as an entrance exam by Milenija, Tetra, GenerIQ, Decima, Nano and other societies. E-mail: predavec@gmail.com
?123, –1135, –2147, –3159, –4??1
421, 526, 842, ?, ?, 5263, ?, 8421
TWO, TEN, SIX, RBK, PQI, NTR, LLD, ?, ?, ?, ?, 586, VO
140, 3, -3, 150, -4, 4, 164, -6, 5, ?, ?, ?, 190, -9
(v – z)(v – ?)(w – ?)(z – ?)(? – ?) = v(xz + wy)(xz – wy) + w(vy + xz)(vy – xz) + x(wz + vy)(wz – vy) + y(vx + wz)(vx – wz) + z(wy + vx)(wy – vx) +
+ v2((x – w)yz + wx(z – y)) + w2(vx(y – z) + (v – x)yz) + x2((w – v)yz + vw(z – y)) + y2(vw(x – z) + (v – w)xz) + z2((w – v)xy + vw(y – x))
1, 1, 0, 1, ?, 2, ?, 5, ?, 13, ?, 34, ?, 89
–0.5, 1, 1, 0, –1, 0, ?, ?, ?
?, 11111011, 11110111, 11110111, 11111011, 11011110, ?
?, LL, 11, 22, ?, 33, ππ
0, 4, 2, 0, 4, 20, ?, ?, 200
220/121, ?, 253/154, ?, ?, 286/187, ?1?/?1?, 72?/?2?, 8??/???, ?
1, ?, 1, ?, 8, ?, 180, 1120, 8064, 725760/11
–240, ?, –132, –78, –56, –34, –12, 10, ?
765, 4462, 20335, 110314, 1031101, 22022022, ?
3, 5, 11, ?, 31, 41, ?, 67, ?, 109
11000000, ?, 110000010, ?, 110010000, 1110100000, 1010100010, 1000101001, ?, 101101010, ?
–1, –1, –1, ?, 399, ?
?, 0, , 2, ?, 2, ?, 2, ?, 4, 3
498, 374, 284, 250, 248, ?, ?, 142, ?, 124
1/2, ?, /2, /2, 1, ?
f(2) = f(4) ; f(e) ≈ 1,444667861 ; f(π) ≈ 1,43961949584759 ; f '(x) · x2 = f(x) · (1 – ln x) ; f(3) ≈ ? ; f2(i) ≈ ?
421, 517, ?, 724, 842, 913, ?, ?, ?
?, ?, 2, 4, ?, ?, 2, 4, 6, ?, ?, ?, 2, 4, 6, ?, ?, ?, ?, ?, ?, 4, 6, 8, ?, ?, ?, ?, ?, 14, ?
eπ + (e – 1)π + A3 + A4 + … = ? where Ai1· Ai2· ... · Aik= Aj1· Aj2· ... · Ajk
whenever i1 + i2 + ... + ik = j1 + j2 + ... + jk for any positive integer k.